![]() ![]() Node(id=4, fullyQualifiedName=) Challenges with Removing Duplicates from An Array in Kotlin Only use this if you want your return type to be an Array.Internally it calls toMutableSet() followed by toList().However, it is not the most efficient one. This is the most flexible way to remove duplicates, as you can still use the original array if you need to. ![]() This function will return a new array that contains only the unique elements from the given array. ![]() Node(id=4, fullyQualifiedName=) Using the distinct() function
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